Q5 of 70 Page 125

□ ABCD is a trapezium such that || . and such that || . Prove that .

Given, ABCD is a trapezium such that || . and such that ||


⟹ First draw DB to intersect MN at P.


Proof : AB || CD and MN || AB


∴ MN || CD


Now, MN || AB and M-P-N


Hence, MP || AP


Similarly, as MN || CD and M-P-N


PN || CD


In ∆ABD, MP || AB


... (i)


In ∆BCD, PN || CD


... (ii)


From eq (i) and (ii)


PROVED.


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