In Δ ABC, the bisector of ∠A intersects
in D. Prove that
and 
Given, In ΔABC, the bisector of ∠A intersects
in D
TO PROVE :
1) 
2) 

Proof: In
ABC, the bisector of
A intersects
in D
∴ ![]()
By applying componendo
∴ ![]()
![]()
By applying invertendo
![]()
BD
...... (i)
Similarly,
![]()
![]()
![]()
![]()
DC =
PROVED.
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