P and Q are the mid-points of
and
in ΔABC. If the area of ΔAPQ = 12√3, find the area of ΔABC.

In ∆ABC, P and Q are mid-points of AB and AC respectively.
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The correspondence ∆APQ↔∆ABC is a similarity by SSS theorem.
Now,
Areas of similar triangles are proportional to the squares of their corresponding sides.
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ABC = 12√3 × 4
ABC = 48√3
The area of ∆ABC is 48√3.
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