The bisector of ∠B intersects
in D. If BA = 12 and BC = 16, AD = 9, then AC = ……
We have

Given: ∠ABD = ∠CBD
BA = 12,
BC = 16 &
AD = 9
To find: AC = ?
∵, In ∆ABC bisector of ∠B intersects AC at D.
By theorem of proportionality, we have
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By reciprocating on both sides,
⇒ ![]()
Substituting the values, we get
⇒ ![]()
⇒ ![]()
⇒ CD = 12
We can express AC as,
AC = AD + CD
⇒ AC = 9 + 12
⇒ AC = 21
Thus, option (b) is correct.
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