Q7 of 70 Page 140

In ΔABC, B—M—C and A—N—C, ||. If NC : NA = 1 : 3 and CM = 4, then BC = ………..

We have the diagram as,



Given: In ∆ABC,


MN ∥ AB


NC:NA = 1:3


⇒


CM = 4


To find: BC = ?


In ∆ABC,


Since, MN ∥ AB


⇒


⇒


⇒ MB = 4 × 3 [∵, ⇒ ]


⇒ MB = 12


In B – M – C,


BC = MB + CM


⇒ BC = 12 + 4


⇒ BC = 16


Thus, option (b) is correct.

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