In □m ABCD, T ∈
and
intersects
in M and
in O. Prove that AM2 = MT • MO.
In
ABCD, T
and
intersects
in M and
in O.

To prove:
AM2 = MT •MO
In ∆AMB and ∆OMD
∠AMD ≅ ∠OMD (Vertically opposite angles)
∠MBA ≅ ∠MDO (Alternate angles)
The correspondence AMD↔OMB is a similarity
…(1)
In ∆AMD and ∆TMB
∠AMD ≅ ∠TMB (Vertically opposite angles)
∠MAD ≅ ∠MTB (Alternate angles)
The correspondence AMD↔TMB is a similarity
…(2)
Multiplying (1) and (2),
![]()
![]()
Hence, AM2 = MT •MO
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