In Δ ABC,
||
, P ∈
, Q ∈
. If 4AP = AB and AQ = 4, then AC =
We have,

Given: In ∆ABC,
PQ ∥ BC,
4 AP = AB &
AQ = 4
To find: AC = ?
We know, 4 AP = AB
⇒
…(i)
In ∆ABC, we know that PQ ∥ BC.
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⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ AC = 4 × 4
⇒ AC = 16
Thus, the option (d) is correct.
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