In ΔABC, M ∈
, N ∈
such that
||
,……….is not true.
We have the diagram as

Given: In ∆ABC, MN ∥ BC.
By property of triangles, we can say that
,
&
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Cross multiplication of the above equations,
⇒ AM × NC = AN × MB
Or AM . NC = AN . MB is true.
AM × AC = AN × AB
Or AM . AC = AN . AB is true.
MB × AC = NC × AB
Or MB . AC = NC . AB is true.
So, AM . MB = AN . NC is not true.
Thus, option (b) is correct.
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