In Δ PQR, P—M—Q and P—N—R. If PQ = 18, PM = 12, PR = 9 and NR = …, then
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We have

Given: P – M – Q and P – N – R
In ∆PQR, MN ∥ QR.
PQ = 18,
PM = 12 &
PR = 9
To find: NR = ?
In ∆PQR, when MN ∥ QR.
⇒ ![]()
Substituting the given values in the above equation,
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⇒ ![]()
⇒ PN = 6
Observe the diagram,
PR = PN + NR
⇒ NR = PR – PN
⇒ NR = 9 – 6
⇒ NR = 3
Thus, option (b) is correct.
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