Justify the following statements with reasons:
The sum of three sides of a triangle is more than the sum of its altitudes.
Consider ΔABC with altitudes as AP, BQ and CR on segments BC, AB and AC respectively

Consider ΔAPC
∠APC = 90° … AP is altitude
∠ACP is some acute angle less than 90°
Hence AC > AP … (i)
Similarly we can prove
BC > CR … (ii)
AB > BQ … (iii)
Adding (i), (ii) and (iii) we get
⇒ AC + BC + AB > AP + CR + BQ
⇒ sum of sides > sum of altitudes
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