In ΔABC, AB = BC and ∠B = 64°. Find ∠C.

In Δ ABC since AB = BC ,so the triangle is isosceles
In an isosceles triangle the base angles are always equal
So ∠A = ∠C = x(Let’s assume)
Since sum of interior angles of a triangle is 1800
∠A + ∠B + ∠C = 1800
⇒ 2x = 1800-640 = 1160
⇒ x = 580
∠A = ∠C = 580
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