In the figure ABCD is a square, M, N, O, and P are the midpoints of sides AB, BC, CD and DA respectively. Identify the congruent triangles.

In Δ APM, Δ BMN, Δ CNO and Δ DOP
AB = BC = CD = DA (Sides of a square)
Since M, N, O, and P are the midpoints of sides AB, BC, CD and DA
⇒ 2AM = 2BN = 2CO = 2DP
⇒ AM = BN = CO = DP …(i)
⇒ 2AP = 2BM = 2CN = 2DO
⇒ AP = BM = CN = DO …(ii)
∠PAM = ∠MBN = ∠NCO = ∠ODP(Angles of a square) …(iii)
So Δ APM ≅ Δ BMN ≅ Δ CNO ≅ Δ DOP by S.A.S. axiom of congruency.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


