In a triangle, ABC, AC = AB, and the altitude AD bisect BC. Prove that ΔADC ≅ ΔADB.

In ΔADC and ΔADB
AC = AB(Given)
BD = DC(AD bisects BC)
AD = AD(Common)
So ΔADC ≅ ΔADB by S.S.S. axiom of congruency
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
