Q1 of 49 Page 61

In a triangle ABC, ∠B = 28° and ∠C = 56°. Find the largest and the smallest sides.

The side opposite to the smallest angle is the smallest side and the angle opposite to the largest angle is the largest side


Since the sum of interior angles of a triangle is 1800


∠A + ∠B + ∠C = 1800


⇒ ∠A = 1800-(28° + 56°)


⇒ ∠A = 960


Since ∠A is the largest angle so BC is the largest side


Since ∠B is the smallest angle so AC is the smallest side


More from this chapter

All 49 →
2

Suppose ABC is a triangle and D is the midpoint of BC. Assume that the perpendiculars from D to AB and AC are of equal length. Prove that ABC is isosceles.

 3

Suppose ABC is a triangle in which BE and CF are respectively the perpendiculars to the sides AC and AB. If BE = CF, prove that triangle ABC is isosceles.

 2

In a triangle ABC, we have AB = 4cm, BC = 5.6cm and CA = 7.6cm. Write the angles of the triangle in ascending order of measures.

 3

Let ABC be a triangle such that ∠B = 70° and ∠C = 40°. Suppose D is a point on BC such that AB = AD. Prove that AB > CD.