Justify the following statements with reasons:
The sum of any two sides of a triangle is greater than twice the median drawn to the third side.
Consider ΔABC and AP is the median as shown BP = PC
Construct PQ such that AP = PQ

Consider ΔAPB and ΔQPC
AP = PQ … construction
∠APB = ∠QCP … vertically opposite angles
BP = PC … AP is median
Thus by SAS test for congruency
ΔAPB ≅ ΔQPC
⇒ AB = CQ … corresponding sides of congruent triangles…(i)
Consider ΔAQC
⇒ AC + CQ > AQ
Using (i)
⇒ AC + AB > AQ
But AQ = AP + PQ and AP = PQ by construction hence AQ = 2AP
⇒ AC + AB > 2AP
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.