Q1 of 49 Page 47

In a ΔABC, AB = AC and ∠A = 50°. Find ∠B and ∠C.


In Δ ABC since AB = AC , so the triangle is isosceles


In an isosceles triangle, the base angles are always equal


So ∠B = ∠C = x(Let’s assume)


Since the sum of interior angles of a triangle is 1800


∠A + ∠B + ∠C = 1800


⇒ 2x = 1800-500 = 1300


⇒ x = 650


∠B = ∠C = 650


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