Q3 of 49 Page 47

In each of the following figure, find the value of x:

Δ ABC is isosceles with AB = AC


∠ABC = ∠ACB = 550 (Base angles are equal)


∠ABC + ∠ACB + ∠BAC = 1800(Sum of interior angles of a triangle)


⇒ ∠BAC = 1800-(550 + 550) = 700


∠BAC-x = 1800-(550 + 750)


⇒ -x = 1800-2000 = -200


⇒ x = 200


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