Let ABC be a triangle. Draw a triangle BDC externally on BC such that AB = BD and AC = CD. Prove that ΔABC ≅ ΔDBC.

In ΔABC and ΔDCB
AB = BD … given
AC = CB … given
BC = BC … common side
Therefore, by SSS test for congruency
ΔABC ≅ ΔDBC
Hence proved
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