Q3 of 49 Page 47

In each of the following figure, find the value of x:

Δ ACD is isosceles where AC = CD


∠DAC = ∠CDA = 300


∠BAD = ∠DAC + ∠CAB


⇒ ∠BAD = 650 + 300 = 950


In Δ ABD,


∠ABD + ∠BDA + ∠DAB = 1800 (Sum of interior angles of a triangle)


x = 1800 –(950 + 300) = 550


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