Q7 of 49 Page 151

In a triangle ABC, AB = AC. Suppose P is a point on AB and Q is a point on AC such that AP = AQ. = Prove that ΔAPC ≅ ΔAQB.


In ΔAPC and ΔAQB


AP = AQ … given


∠BAQ = ∠CAP … ∠A common angle


AB = AC … given


Therefore, by SAS test for congruency


ΔAPC ≅ ΔAQB


Hence proved


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