Q1 of 49 Page 51

In the given figure, If AB || DC and P is the midpoint of BD, prove that P is also the midpoint of AC.

In Δ DPC and Δ APB we have


DP = PB(P is the midpoint of BD)


∠DPC = ∠APB( Vertically Opposite)


∠DCP = ∠PAB (Alternate interior angle)


So Δ DPC and Δ APB are congruent to each other by A.A,S. axiom of congruency


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