If the sum of squares of the zeroes of the quadratic polynomial x2 – 8x + k is 40, find k.
Given : p(x) = x2 – 8x + k
α2 + β2 = 40
We have,
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and ![]()
So,
…(1)
…(2)
Now, if we recall the identities
(a + b)2 = a2 + b2 + 2ab
Using the identity, we get
(α + β)2 = α2 + β2 + 2 αβ
(8)2 =
+ 2(k)
⇒2k = 64 – 40
=
= 12
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