Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2 and find the quotient and the remainder. Is 1 + 2x + x2 a factor of 3x3 + x2 + 2x + 5![]()
Dividend = 3x3 + x2 + 2x + 5
Divisor = x2 + 2x + 1
Now, dividend and divisor both are in the standard form.
Now, on dividing p(x) by g(x) we get the following division process

Quotient = 3x – 5
Remainder = 9x + 10
No, x2 + 2x + 1 is not a factor of 3x3 + x2 + 2x + 5 because remainder ≠ 0
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