If one zero of the polynomial (α2 + 9) x2 + 13x + 6α is reciprocal of the other, find the value of a.
Let one zero of the given polynomial is ![]()
According to the given condition,
The other zero of the polynomial is ![]()
We have,
Product of zeroes, ![]()
![]()
⇒ α2 – 6α + 9 = 0
⇒ α2 – 3α – 3α + 9 = 0
⇒ α(α – 3) – 3(α – 3) = 0
⇒(α – 3)(α – 3) = 0
⇒(α – 3) = 0 & (α – 3) = 0
⇒ α = 3, 3
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