Verify that the numbers given alongside of the cubic polynomial are their zeros. Also verify the relationship between the zeroes and the coefficients in each case :
x3 + 2x2 – x – 2; – 2 – 2, 1
Let p(x) = x3 + 2x2 – x – 2
Then, p( – 2) = ( – 2)3 + 2( – 2)2 – ( – 2) – 2
= – 8 + 8 + 2 – 2
= 0
p(1) = (1)3 + 2(1)2 – (1) – 2
= 1 + 2 – 1 – 2
= 0
Hence, – 2, – 2 and 1 are the zeroes of the given polynomial x3 + 2x2 – x – 2.
Now, Let α = – 2 , β = – 2 and γ = 1
Then, α + β + γ = – 2 + ( – 2) + 1 = – 3
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αβ + βγ + γα = ( – 2)( – 2) + ( – 2)(1) + (1)( – 2)
= 4 – 2 – 2
= 0
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and αβγ = ( – 2) × ( – 2) × 1
= 4
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Thus, the relationship between the zeroes and the coefficients is not verified.
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