Q10 of 90 Page 2

Find quadratic polynomial whose zeroes are :

Let the zeroes of the quadratic polynomial be


α = 3 + √7, β = 3 – √7


Then, α + β = 3 + √7 + 3 – √7 = 6


αβ = (3 + √(7)) × (3 – √7) = 9 – 7 = 2


Sum of zeroes = α + β = 6


Product of zeroes = αβ = 2


Then, the quadratic polynomial


= x2 – (sum of zeroes)x + product of zeroes


= x2 – (6)x + 2


= x2 – 6x + 2


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