If (x + a) is a factor 2x2 + 2ax + 5x + 10, find a.
Given x + a is a factor of ![]()
So,
g(x) = x + a
x + a = 0
⇒x = – a
Putting the value x = – a in the given polynomial, we get
2( – a)2 + 2a( – a) + 5( – a) + 10 = 0
2a2 – 2a2 – 5a + 10 = 0
– 5a + 10 = 0
![]()
a = 2
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