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Q9 of 90 Page 2

Find all the zeroes of the polynomial given below having given numbers as its zeroes.

x3 + 5x2 + 7x + 3; – 3

Given zeroes is – 3


So, (x + 3) is the factor of x3 + 5x2 + 7x + 3


Let us divide x3 + 5x2 + 7x + 3 by x + 3


The division process is



Here, quotient = x2 + 2x + 1


= (x + 1)2


So, the zeroes are – 1 and – 1


Hence, all the zeroes of the given polynomial are – 1, – 1 and – 3.


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Questions · 90
2. Polynomials
1 2 3 1 1 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 4 5 6 7 8 8 8 9 9 9 9 9 9 10 10 10 10 10 10 11 12 12 13 13 1 2 3 3 3 3 3 3 3 3 4 5 6 6 6 6 6 6 7 7 7 7 7 7 8 9 9 9 9 9 9 9 9 9 10 11 11 11 11 12 13 14 15 15 15 15
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