Find all the zeroes of the polynomial given below having given numbers as its zeroes.
x3 – 6x2 + 11x – 6;3
Given zeroes is 3
So, (x – 3) is the factor of x3 – 6x2 + 11x – 6
Let us divide x3 – 6x2 + 11x – 6 by x – 3
The division process is

Here, quotient = x2 – 3x + 2
= x2 – 2x – x + 2
= x(x – 2) – 1(x – 2)
= (x – 1)(x – 2)
So, the zeroes are 1 and 2
Hence, all the zeroes of the given polynomial are 1, 2 and 3.
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