Find all the zeroes of the polynomial given below having given numbers as its zeroes.
2x3 – 4x – x2 + 2;√2, – √2
2x3 – 4x – x2 + 2;√2, – √2
Given zeroes are √2 and – √2
So, (x – √2) and (x + √2) are the factors of 2x3 – 4x – x2 + 2
⟹ (x – √2)(x + √2) = x2 – 2 is a factor of given polynomial.
Consequently, x2 – 2 is also a factor of the given polynomial.
Now, let us divide 2x3 – 4x – x2 + 2by x2 – 2
The division process is

Here, quotient = 2x – 1
So, the zeroes is ![]()
Hence, all the zeroes of the given polynomial are
,
and ![]()
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