A conducting square loop having edges of length 2.0 cm is rotated through 180° about a diagonal in 0.20 s. A magnetic field B exists in the region which is perpendicular to the loop in its initial position. If the average induced emf during the rotation is 20 mV, find the magnitude of the magnetic field
Given:
Average induced emf in the loop![]()
Time taken to rotate the loo ![]()
Edge length of square loop ![]()
Area of square loop ![]()
We know that,
Average induced emf in time interval Δt is given by
…(i)
Where
are flux across the cross section at time intervals
respectively.
Magnetic flux(ϕ) through the loop is given by the formula
![]()
![]()
Where B=magnetic field intensity
A=area of cross section
θ =angle between area vector and magnetic field
Initially, angle between area vector and magnetic field is 0°
Therefore, initial flux through the coil is
![]()
When it is rotated by 180° flux passing through the coil is given by
![]()
Putting this values in eqn.(i) we get,
![]()
Putting the values of ϵ, B and Δt in the above eqn.
![]()
![]()
Therefore, magnitude of magnetic field intensity is 5T
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