A circular coil of radius 2.00 cm has 50 turns. A uniform magnetic field B = 0.200 T exists in the space in a direction parallel to the axis of the loop. The coil is now rotated about a diameter through an angle of 60.0°. The operation takes 0.100s.
(a) Find the average emf induced in the coil.
(b) If the coil is a closed one (with the two ends joined together) and has a resistance of 4.00 Ω, calculate the net charge crossing a cross-section of the wire of the coil.
Given:
Radius of coil ![]()
No. of turns in the coil ![]()
Magnetic field intensity ![]()
We know that,
Flux (ϕ) of magnetic field (B) through the loop of cross section area A in the magnetic field is given by
![]()
![]()
Where N=no. of turns in the coil
Since magnetic field is perpendicular to the loop the flux becomes
![]()
Initial flux through the coil is given by
![]()
After 0.1 s the coil is rotated through an angle of 60° =θ
Finally, the flux through the coil becomes
![]()
Average induced emf in time interval Δt is given by
…(i)
Where
are flux across the cross section at time intervals
respectively.
Using eqn.(i) emf induced in the coil is given by

Putting the values of N, B, A and Δt in above eqn. we get
![]()
Therefore average emf induced in the coil is ![]()
(b) the current through the coil (i) is calculated using formula
![]()
Hence the charge(Q) crossing the cross-section of the wire in time interval Δt is
![]()
Putting the values of ϵ, R and Δt we get,
![]()
Therefore charge crossing cross-section of the wire in the coil is ![]()
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