Consider a variation of the previous problem figure. Suppose the circular loop lies in a vertical plane. The rod has a mass m. The rod and the loop have negligible resistances but the wire connecting O and C has a resistance R. The rod is made to rotate with a uniform angular velocity ω in the clockwise direction by applying a force at the midpoint of OA in a direction perpendicular to it. Find the magnitude of this force when the rod makes an angle θ with the vertical.
When the circular loop is in the vertical plane, it tends to rotate in the clockwise direction because of its weight.
Let the force applied be F and its direction be perpendicular to the rod.
The component of mg along F is mg sin θ.
The magnetic force is in perpendicular and opposite direction to mg sin θ.

Now, Current in the rod will be
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The force on the rod will be
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So, the net force will be
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The net force passes through the centre of mass of the rod.
Net torque on the rod about the centre O will be

Because the rod rotates with a constant angular velocity, the net torque on it is zero.
Thus,![]()

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