ABCD is a quadrilateral with AB parallel to CD. A line drawn parallel to AB meets AD at P and BC at Q. Prove that
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Given: ABCD is a quadrilateral with AB parallel to CD and line drawn parallel to AB meets AD at P and BC at Q

Required: To prove ![]()
Construction: draw a diagonal AC, which intersects PQ at R
Now, in ΔABC
Here, QR||AB
∴ By Thales theorem ![]()
⇒
--eq(1)
Now, consider ΔACD
Here, RP||DC
∴ By Thales theorem
--eq(2)
From --eq(1) and –eq(2)
We have,
![]()
∴ ![]()
Hence Proved
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