Q7 of 62 Page 180

In the figure, DE||AQ and DF||AR

Prove that EF||QR.


Given: DE||AQ and DF||AR

Required: To prove EF||QR.


Consider ΔAPQ


Here, ED||QA


∴ By Thales theorem --eq(1)


Now, Consider ΔPAR


Here, DF||AR


∴ By Thales theorem --eq(2)


From –eq(1) and –eq(2), we can see that



∴ By Converse Thales theorem we can say that EF||QR in ΔPQR (∵)


Hence Proved


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