Q13 of 62 Page 193

In the adjoining figure, chords AB and CD intersect at P.

If AB = 16 cm, PD = 8 cm, PC = 6 and AP >PB, then AP =


Given: AB = 16 cm, PD = 8 cm, and PC = 6 cm


We know that two chords AB and CD intersect at P inside the circle with centre at O.


Then PA× PB = PC× PD.


Let PA = x then PB = AB – AP = 16 – x


x × (16–x) = 6× 8


16x – x2 =48


x2 – (12+4)x + 48 = 0


(x–12)(x –4) =0


x = 4 and 12


x = 4 is not possible because AP >PB


AP = 12 cm

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