Q14 of 62 Page 193

A point P is 26 cm away from the centre O of a circle and PT is the tangent drawn from P to the circle is 10 cm, then OT is equal to


Given: OP = 26 cm, PT = 10 cm


We know that a tangent at any point on a circle is perpendicular to the radius through the point of contact


⇒ ∠ OTP = 90°


Using Pythagoras theorem,


OP2 = PT2 + OT2


⇒ OT2 = OP2 – PT2


⇒ OT2 = 262 – 102


⇒ OT = 24 cm

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