Q19 of 62 Page 193

The areas of two similar triangles are 16 cm2 and 36 cm2 respectively. If the altitude of the first triangle is 3 cm, then the corresponding altitude of the other triangle is

Given: ar(ABC) = 16 cm2, ar(DEF) = 36 cm2 and altitude of first triangle = 3 cm


Areas of two similar triangles are in the ratio 16:36 = 4: 9


We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of


their corresponding sides or altitudes



Putting the values



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