In the figure TP is a tangent to a circle. A and B are two points on the circle. If ∠BTP = 72° and ∠ATB = 43° find ∠ABT.

The alternate segment theorem (also known as the tangent-chord theorem) states that in any circle, the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.
Therefore by above theorem,
∠BAT = ∠BTP = 72°
Sum of all angles of a triangle = 180°
In ΔABT,
∠ABT + ∠BTA + ∠TAB = 180°
⇒ ∠ABT + 43° + 72° = 180°
⇒ ∠ABT + 115° = 180°
⇒ ∠ABT = 180° – 115°
⇒ ∠ABT = 65°
Hence, ∠ABT = 65°
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