Q2 of 62 Page 193

In Δ ABC, DE is || to BC, meeting AB and AC at D and E.

If AD = 3 cm, DB = 2 cm and AE = 2.7 cm, then AC is equal to

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Given: DE intersect AB and AC and DE || BC


AD = 3 cm, DB = 2 cm and AE = 2.7 cm


Using Basic Proportionality theorem which states that if a straight line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the ratio



Putting the values,




Now, AC = AE + EC = 2.7 +1.8 = 4.5 cm

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