Q3 of 62 Page 193

In ΔPQR, RS is the bisector of ∠R. If PQ = 6 cm, QR = 8 cm, RP = 4 cm then PS is equal to

Given: ∠ PRS =∠ SRQ and PQ = 6 cm, QR = 8 cm, RP = 4 cm


Using Angle Bisector Theorem which states that the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the corresponding sides containing the angle


Here, RS is the bisector of ∠ A so



Let PS be x then SQ will be 6– x.






So, PS = 2 cm

More from this chapter

All 62 →
1

If a straight line intersects the sides AB and AC of a ΔABC at D and E respectively and is parallel to BC, then =

 2

In Δ ABC, DE is || to BC, meeting AB and AC at D and E.

If AD = 3 cm, DB = 2 cm and AE = 2.7 cm, then AC is equal to

 4

In figure, if , ∠B = 40°, and ∠C = 60°, then ∠BAD =

 5

In the figure, the value x is equal to