Q9 of 62 Page 180

In a ΔABC, AD is the internal bisector of ∠A, meeting BC at D.

If BD = 2 cm, AB = 5 cm, DC = 3 cm find AC.

Given: A ΔABC with AD as internal bisector of ∠A, meeting BC at D. and BD = 2 cm, AB = 5 cm, DC = 3 cm


Required: The length of AC


Here, In ΔABC AD is the internal bisector of ∠A


∴ By angle bisector theorem


⇒


⇒


∴ AC = 7.5cm


∴ Length of AC = 7.5 cm


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