Q15 of 62 Page 193

In the figure, if ∠PAB = 120° then ∠BPT =

From the figure, we find that ABCP is a cyclic quadrilateral


∵Opposite angles are supplementary


∴∠ BAP + ∠ PCB = 180°


⇒ ∠ PCB = 180° – ∠ BAP


⇒ ∠ PCB = 180° – 120°


⇒ ∠ PCB = 60°


Now, using Tangent–Chord theorem


∠ PCB = ∠ BPT


⇒ ∠ BPT = 60°

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