Q9 of 62 Page 180

In a ΔABC, AD is the internal bisector of ∠A, meeting BC at D.

If AB = 5.6 cm, AC = 6 cm and DC = 3 cm find BC.

Given: A ABC with AD as internal bisector of A, meeting BC at D. and AB = 5.6 cm, AC = 6 cm, DC = 3 cm


Required: The length of BC


Here, In ΔABC AD is the internal bisector of ∠A


∴ By angle bisector theorem


⇒


⇒


∴ BD = 2.8cm


∴ Length of BD = 2.8 cm


More from this chapter

All 62 →
8

In the figure DE||AB and DF||AC.

Prove that EF||BC.


 9

In a ΔABC, AD is the internal bisector of ∠A, meeting BC at D.

If BD = 2 cm, AB = 5 cm, DC = 3 cm find AC.

 9

In a ΔABC, AD is the internal bisector of ∠A, meeting BC at D.

If AB = x, AC = x–2, BD = x + 2 and DC = x–1 find the value of x.

 10

Check whether AD is the bisector of ∠A of ΔABC in each of the following.

AB = 4 cm, AC = 6 cm, BD = 1.6 cm, and CD = 2.4 cm.