Q10 of 141 Page 400

Prove that the diameter of a circle perpendicular to one of the two parallel chords of a circle is perpendicular to the other and bisects it.

∠PFD = ∠PEB [equal to 90°]


∴PFCD and OFCD


We know that the perpendicular from the center of a circle to chord, bisect the chord.


Therefore,


CF = FD Proved.


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