In the adjoining figure,
and
are two equal chords of a circle with center
Show that
lies on the bisector of ![]()

In triangle OAB and triangle OAC,
AB = AC [Given]
OB = CO [Radius]
OA = OA [Common]
By side-side-side criterion of congruence
ΔOAB ≅ ΔOAC
∴ ∠OAB = ∠OAC Proved.
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