Q21 of 141 Page 438

is a rectangle. Prove that the center of the circle through is the point of intersection of its diagonals.

Let O be the point of intersection of the diagonals BD and AC of rectangle ABCD.


Since, the diagonals of a rectangle are equal and bisect each other.



∴ OA = OB = OC = OD


Hence, O is the center of the circle through A, B, C, D.


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