Q4 of 141 Page 420

In the given figure, is the center of the circle. If and find

In triangle ABD,


∠ABD + ∠BAD + ∠ADB = 180°[Sum of angles of triangle]


⇒ 35°+ 90° + ∠ADB = 180°


⇒ ∠ADB = 55°


∴ ∠ACB = ∠ADB = 55°[Angles in the same segment of a circle]


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