Q24 of 141 Page 447

In the give figure, and are two intersecting chords of a circle. If ∠CAB = 40° and ∠BCD = 80°, then ∠CBD = ?

Given: and ∠BCD = 80°


Here,


∠CAB = ∠CDB = 40° ( angles in the same segment drawn from same chord are equal).


Now, in ΔBCD


By angle sum property


∠BCD + ∠CDB + ∠CBD = 180°


80° + 40° + ∠CBD = 180°


∠CBD = 180° – 40° – 80°


∠CBD = 60°


∴ ∠CBD = 60°

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