Q7 of 141 Page 420

In the adjoining figure, is a chord parallel to diameter of the circle with center If calculate

∠CAD and ∠CBD are in the segment BD.


∴ ∠CAD = ∠CBD [Angles in the same segment of a circle]


∠CAD = 60°


In triangle ACD,


∠CAD + ∠ADC + ∠ACD = 180°[Sum of angles of triangle]


⇒ 60° + 90° + ∠ACD = 180°


⇒ 150° + ∠ACD = 180°


⇒ ∠ACD = 30°


∴ ∠CDE = ∠ACD = 30°[Alternate angles]


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